It worked.
Initially I didn't understand what you mean but after some googleing I
figured it out what I had to do so I did this
instance Show a ⇒ Show (Stack a) where
show s = ...
Now, thinking about this, it totally makes sense because Stack cannot
be an instance of Show if the type a is no
Hi,
You might need a class constraint.
instance (Show a) => Show (Stack a) where
This basically lets Haskell know that if your "a" type is Showable then "Stack
a" is also Showable.
Let me know if this works.
Cheers,
Mark Spezzano
On 31/07/2011, at 6:49 PM, Ovidiu Deac wrote:
> For some re
