According to map's definition, we know the 'fs' should be a list of function. so 'p' need a [a->b] as its parameter. And the result of 'p' should be a list of function which accepts [a] and return [b].
So the type of 'p' is [a->b] -> [[a] -> [b]] hope i make it clear. ----- e^(π.i) + 1 = 0 -- View this message in context: http://haskell.1045720.n5.nabble.com/Beginners-help-tp3306796p3307470.html Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
