To get exact fractions, use the Ratio module (import Ratio) and the
Rational type which is defined there.
Thanks dude, it works
The code you wrote below has a serious style problem that I thought
I'd point out: you shouldn't use the IO monad for pure functions.
I've never known that, th
On 7/19/05, Cale Gibbard <[EMAIL PROTECTED]> wrote:
> The code you wrote below has a serious style problem that I thought
> I'd point out: you shouldn't use the IO monad for pure functions. You
> can define f as follows:
> [snip]
I agree on the stylistic front. Another approach is to make the
gene
To get exact fractions, use the Ratio module (import Ratio) and the
Rational type which is defined there.
The code you wrote below has a serious style problem that I thought
I'd point out: you shouldn't use the IO monad for pure functions. You
can define f as follows:
f x = let t = 2 * x
i
So there's no way to get exact stream that represents a fraction, such as:
.5 = .1
.2 = .00110011001100110011
???
From: Udo Stenzel <[EMAIL PROTECTED]>
To: Dinh Tien Tuan Anh <[EMAIL PROTECTED]>
Subject: Re: [Haskell-cafe] Error with Float
From: Cale Gibbard <[EMAIL PROTECTED]>
Reply-To: Cale Gibbard <[EMAIL PROTECTED]>
To: Dinh Tien Tuan Anh <[EMAIL PROTECTED]>
CC: haskell-cafe@haskell.org
Subject: Re: [Haskell-cafe] Error with Float
Date: Tue, 19 Jul 2005 11:00:34 -0400
Perhaps you mean:
f x
| x < 1
Perhaps you mean:
f x
| x < 1 = 0 : f (2*x)
| otherwise = 1 : f (2*(x-1))
Note that in the second case, the 1 is subtracted before multiplication by 2.
If you were referring to the problem that this eventually gives
constantly 0 for values like 0.6, try importing the Ratio module and
Opps, its 0:f t
not 0:: f t
and the same for 1:f (t-1)
From: "Dinh Tien Tuan Anh" <[EMAIL PROTECTED]>
To: haskell-cafe@haskell.org
Subject: [Haskell-cafe] Error with Float
Date: Tue, 19 Jul 2005 14:48:55 +
This is my function to convert a fraction (0I guess there
This is my function to convert a fraction (0I guess there's nothing wrong with that, but when traced, it has something
like 0.6*2 - 1 = 0.61
This error got accumulated and made my f function wrong (will eventually
evaluate an infinite 0, no matter what value of x)
Please tell me there's s
