On Tue, 3 Jul 2007, Peter Verswyvelen wrote:
> Let's see
>
> id :: a -> a
>
> curry :: ((a,b) -> c) -> a -> b -> c
>
> => curry id :: ((a,b) -> (a,b)) -> a -> b -> (a,b)
>
> So basically if
>
> f = curry id
>
> then
>
> f x y = (x,y)
>
> which means
>
> curry id = (,)
>
> something like this?
Yo
ething like this?
Do I win a price now? ;)
-Original Message-
From: Henning Thielemann [mailto:[EMAIL PROTECTED]
Sent: Tuesday, July 03, 2007 3:21 PM
To: Peter Verswyvelen
Cc: Haskell-Cafe@haskell.org
Subject: Re: [Haskell-cafe] Haskell's currying and partial application
Henning Thielemann wrote:
On Tue, 3 Jul 2007, Peter Verswyvelen wrote:
IMHO when reading
http://haskell.org/haskellwiki/Currying
a newbie like me cannot see the difference between currying and partial
application...
Better now?
Much better, IMO, although I still don't like the part with
On Tue, 3 Jul 2007, Peter Verswyvelen wrote:
> IMHO when reading
>
> http://haskell.org/haskellwiki/Currying
>
> a newbie like me cannot see the difference between currying and partial
> application...
Better now?
___
Haskell-Cafe mailing list
Haskell
2007 01:48 PM
>Aan: 'Peter Verswyvelen'
>CC: Haskell-Cafe@haskell.org
>Onderwerp: Re: [Haskell-cafe] Haskell's currying and partial application
>
>
>On Tue, 3 Jul 2007, Peter Verswyvelen wrote:
>
>> Ah, thanks for the correction. So if I understand it correctly
On Tue, 3 Jul 2007, Peter Verswyvelen wrote:
> Ah, thanks for the correction. So if I understand it correctly, this is
> currying:
See also:
http://haskell.org/haskellwiki/Currying
http://haskell.org/haskellwiki/Partial_application
and more generally:
http://haskell.org/haskellwiki/Category
