Brandon S Allbery KF8NH allbery at ece.cmu.edu writes:
type Tensor u v =
(u ~ Vect k a, v ~ Vect k b) = Vect k (TensorBasis a b) -- **
IIRC this actually substitutes as
(forall k a b. (u ~ Vect k a, v ~ Vect k b) = Vect k (TensorBasis a b))
and the implicit forall will
This works:
-- Tensor product of two vector spaces
type family Tensor u v :: *
type instance Tensor (Vect k a) (Vect k b) = Vect k (TensorBasis a b)
On Aug 21, 2010, at 9:15 AM, DavidA wrote:
Brandon S Allbery KF8NH allbery at ece.cmu.edu writes:
type Tensor u v =
(u ~ Vect k a, v ~
