[EMAIL PROTECTED] writes:
increment b = b + 1
This is also called 'succ' (for successor).
main = dolet b = 0
let c = randomRIO (1,2)
until (c == 1) increment b
return b
ERROR StPetersburg.hs:8 - Type error in application
*** Expression
* [EMAIL PROTECTED] wrote:
I'm trying to program an implementation of the St. Petersburg game in
Haskell. There is a coin toss implied, and the random-number generation is
driving me quite mad. So far, I've tried this:
import Random
import System.Random -- time goes on, interfaces change
main = do let b = 0
let c = randomRIO (1,2)
until (c == 1) increment b
return b
This is intended to print the number of consecutive heads (i.e., 2)
before
the first tail, but I get the following error:
ERROR StPetersburg.hs:8 - Type
On Nov 27, 2007 1:27 PM, [EMAIL PROTECTED] wrote:
Hello,
I'm trying to program an implementation of the St. Petersburg game in
Haskell. There is a coin toss implied, and the random-number generation is
driving me quite mad. So far, I've tried this:
Yeah, random number generation is one of
Hola Manolo,
What you are trying to do is very easy in Haskell, but you'd better
change the approach.
In short, you are trying to use b as if it was a mutable variable,
which it is not!
One could rewrite your program using mutable variables, as below:
import Data.IORef
import Random
On Tue, 27 Nov 2007 [EMAIL PROTECTED] wrote:
Hello,
I'm trying to program an implementation of the St. Petersburg game in
Haskell. There is a coin toss implied, and the random-number generation is
driving me quite mad. So far, I've tried this:
import Random
increment :: Int - Int
