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On May 7, 2009, at 14:03 , Magnus Therning wrote:
adam vogt wrote:
This is most likely attributable to the use of different compilers.
I don't see how accepting such a variant can cause ambiguity, but I'm
not quite sure whether it is legal H98.
Ju
adam vogt wrote:
This is most likely attributable to the use of different compilers.
I don't see how accepting such a variant can cause ambiguity, but I'm
not quite sure whether it is legal H98.
Just a bit curious then what compiler Brandon was using. I'm using GHC
6.10.2 on AMD64 Linux (Arc
This is most likely attributable to the use of different compilers.
I don't see how accepting such a variant can cause ambiguity, but I'm
not quite sure whether it is legal H98.
On 5/6/09, Magnus Therning wrote:
> Brandon S. Allbery KF8NH wrote:
> > On May 6, 2009, at 12:18 , Nico Rolle wrote:
>
Brandon S. Allbery KF8NH wrote:
On May 6, 2009, at 12:18 , Nico Rolle wrote:
why does this don't work?
test = let a = (>)
in 1 `a` 2
Works fine here once I correct your indentation (the "in" needs to be
indented at least as far as the "l" in "let").
Really? For me it's enough to have
Oh sorry guys was rlly a stupid indentation mistake
next time i'll post the error message too
thanks
regards
2009/5/6 Brandon S. Allbery KF8NH :
> On May 6, 2009, at 12:18 , Nico Rolle wrote:
>>
>> why does this don't work?
>>
>> test = let a = (>)
>> in 1 `a` 2
>
>
> Works fine here once I corr
On May 6, 2009, at 12:18 , Nico Rolle wrote:
why does this don't work?
test = let a = (>)
in 1 `a` 2
Works fine here once I correct your indentation (the "in" needs to be
indented at least as far as the "l" in "let").
--
brandon s. allbery [solaris,freebsd,perl,pugs,haskell] allb...@kf
hi
why does this don't work?
test = let a = (>)
in 1 `a` 2
regards
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