Joe Fredette ha scritto:
You know, I hear theres this brilliant program for compiling C code --
gcd? ccg? gcc, yah gcc... Anyone tried it?
In all seriousness though, why do you need to compile c with ghc? I'm
curious, it seems a bit pointless...
It's for a possible extension I'm planning f
Yhc used to do this (when you could still build it). Turns out that on
Windows using gcc that gets installed with ghc isn't particularly fun,
while ghc makes a very pleasant build experience. Something to do with
directory layouts, head file searching, and what is on the %PATH% by
default.
Thanks
You know, I hear theres this brilliant program for compiling C code --
gcd? ccg? gcc, yah gcc... Anyone tried it?
In all seriousness though, why do you need to compile c with ghc? I'm
curious, it seems a bit pointless...
/Joe
Manlio Perillo wrote:
Anton Tayanovskyy ha scritto:
Works for m
Anton Tayanovskyy ha scritto:
Works for me without the --make, as `ghc foo.c`
For me, too, thanks.
Manlio
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Works for me without the --make, as `ghc foo.c`
--A
On Tue, Mar 17, 2009 at 6:32 PM, Manlio Perillo
wrote:
> Hi.
>
> I'm checking if it possible to build an executable from C source files only.
>
> As an example:
>
> #include
>
> int main () {
> printf("hello world\n");
> return 0;
> }
>
Hi.
I'm checking if it possible to build an executable from C source files only.
As an example:
#include
int main () {
printf("hello world\n");
return 0;
}
$ghc --make foo.c
However this only produces the object file, foo.o; it does not build the
executable file.
What is the r