On Wed, 2012-08-08 at 10:26 -0400, Ryan Smith wrote:
> Right. you also need to calculate what you send to the web server. So you
> need to calculate the request headers when you make a request. Then on the
> response you get response body size and header size. As far as I know
> thats all you ne
Hi Jean Marc,
I believe Sam is right, counting the bytes is the only way I can see
in order to do what you are trying to achieve.
It's a bit annoying the way to do that: you need to create a socket
factory (that wraps normal sockets with your bytes-counting ones) and
register that socket factory
Jean-Marc,
What are you comparing it to in order to determine accuracy? If you're
looking at the "on-the-wire" size (e.g. through a packet capture,
router/switch/interface counters, etc), then that will be counting
Ethernet, IP, TCP and potentially other headers too. The size of such
headers is no
Right. you also need to calculate what you send to the web server. So you
need to calculate the request headers when you make a request. Then on the
response you get response body size and header size. As far as I know
thats all you need to account for. Maybe Oleg or someone else can verify.
O
Hi Ryan,
This will calculate the header size. But is there anything else? Is
the size only headers + URL lenght for the request, and
headers+respons body for the respons? Is there any other CRC,
validation, packet, etc.?
Because headersize + body lenght seems to not be accurate :(
2012/8/8, Ryan
If HttpClient has a method to do this, can someone let me know? This is a
method I wrote to calculate header size:
public static int getHeaderByteSize(Header[] headers) {
int requestHeaderByteSize = 0;
for (Header requestHeader : headers) {
if (requestHeader.getName() != null) {
requestHeaderByte
Hi,
Is there a good way to calculate the bandwidth used by a request?
I'm doing a get and I try to track the upload and download bandwidth used.
So for a get, there is some upload to the server. There is the URL,
and the headers. But seems there is a bit more than that and I'm not
able to figure
