Re: Problem resolving JCL SET symbol

2006-12-21 Thread Jack Kelly
Or if it's SAS, you could concatenate a SAS OPTION statement before the SAS source. Jack Kelly LA Systems @ US Courts x 202-502-2390 -- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [EMAIL PROTECT

Re: Problem resolving JCL SET symbol

2006-12-21 Thread Paul Gilmartin
In a recent note, R.S. said: > Date: Thu, 21 Dec 2006 12:58:43 +0100 > > > > I tried to understand both JCL Reference and UG (the latter not > > even giving a single hit when doing a fuzzy search for 'symbol' > > ...) but came up clueless. > In #<<< 5.4.2.1 "z/OS V1R7.0 MVS JCL Reference

Re: Problem resolving JCL SET symbol

2006-12-21 Thread Alan Brown
How about . // SET QUOT = // SET X = SUCCESS // SET A=&X // SET B="&A=&X" //STEPA EXEC PGM=IEFBR14,PARM ="&A" //STEPB EXEC PGM=IEFBR14,PARM ="&B" Alan Brown Princeton Softech (609) 627-5598

Re: Problem resolving JCL SET symbol

2006-12-21 Thread Robert Bardos
Peter Hunkeler replied: > Betreff: Re: Problem resolving JCL SET symbol > > > > //SASPROC ENTRY=SASXAL0, > > // OPTIONS=, > > // SORT=4 > > > //* > > //SAS

Re: Problem resolving JCL SET symbol

2006-12-21 Thread Hunkeler Peter (KIUK 3)
> //SASPROC ENTRY=SASXAL0, > // OPTIONS=, > // SORT=4 > //* > //SAS EXEC PGM=&ENTRY,PARM='SORT=&SORT &OPTIONS' How about: //STEP1 EXEC PROC=SAS, // PARM.SAS='SORT=4 add whatever parms you need he

Re: Problem resolving JCL SET symbol

2006-12-21 Thread Roger Bowler
On Thu, 21 Dec 2006 12:44:58 +0100, Robert Bardos wrote: > How can I get &X resolved in STEPB in the following stripped down example: > // SET X=SUCCESS > // SET A=&X > // SET B='A=&X' > //STEPA EXEC PGM=IEFBR14,PARM='&A' > //STEPB EXEC PGM=IEFBR14,PARM='&B' Surprisingly, it

Re: Problem resolving JCL SET symbol

2006-12-21 Thread Robert Bardos
cht- > Von: IBM Mainframe Discussion List > [mailto:[EMAIL PROTECTED] > Auftrag von Terry Sambrooks > Gesendet: Donnerstag, 21. Dezember 2006 13:49 > An: IBM-MAIN@BAMA.UA.EDU > Betreff: Re: Problem resolving JCL SET symbol > > > Hi > > In respect of the SET symbol

Re: Problem resolving JCL SET symbol

2006-12-21 Thread R.S.
Robert Bardos wrote: Radoslaw Skorupka (hope I got the spelling right) wrote: What's your problem ? You don't have to investigate how would it work, you can TRY IT. Radoslaw, what in my original post made you think that I did not try it? Misunderstanding ;-) I read it "at low brain

Re: Problem resolving JCL SET symbol

2006-12-21 Thread Terry Sambrooks
Hi In respect of the SET symbol problem, the following may be acceptable. // SET X=SUCCESS // SET A=&X // SET SIGN='=' // SET B=&A.&SIGN.&X //STEPA EXEC PGM=IEFBR14,PARM='&A' //STEPB EXEC PGM=IEFBR14,PARM='&B' The problem

Re: Problem resolving JCL SET symbol

2006-12-21 Thread Robert Bardos
Radoslaw Skorupka (hope I got the spelling right) wrote: > What's your problem ? > You don't have to investigate how would it work, you can TRY IT. Radoslaw, what in my original post made you think that I did not try it? Robert --

Re: Problem resolving JCL SET symbol

2006-12-21 Thread R.S.
Robert Bardos wrote: Folks, once again I'm drawing blanks. How can I get &X resolved in STEPB in the following stripped down example: // SET X=SUCCESS // SET A=&X // SET B='A=&X' //STEPA EXEC PGM=IEFBR14,PARM='&A' //STEPB EXEC PGM=IEFBR14,PARM='&B' I tried to unders

Problem resolving JCL SET symbol

2006-12-21 Thread Robert Bardos
Folks, once again I'm drawing blanks. How can I get &X resolved in STEPB in the following stripped down example: // SET X=SUCCESS // SET A=&X // SET B='A=&X' //STEPA EXEC PGM=IEFBR14,PARM='&A' //STEPB EXEC PGM=IEFBR14,PARM='&B' I tried to understand both JCL Reference