Hello! I want to figure out how to draw a sin wave between two QPointF’s using
QPainterPath. Calculating the cubic control points seems like the best way, but
I am far from mastering that theory.
This is a diagramming app and the goal is to get a squiggly line between two
objects.
Thanks!
smi
You can just compute the sine directly :
for(int i = 0; i < width; i++)
{
int x = i;
int y = height / 2 + amplitude * std::sin(2 * M_PI * freq * i / width
+ phase);
path.lineTo(x, y);
}
---
Jean-Michaël Celerier
http://www.jcelerier.name
On Thu, Jul 20, 2017 at 9:
2017-07-20 10:23 GMT+02:00 Jean-Michaël Celerier
:
> You can just compute the sine directly :
>
>for(int i = 0; i < width; i++)
>{
> int x = i;
> int y = height / 2 + amplitude * std::sin(2 * M_PI * freq * i / width +
> phase);
> path.lineTo(x, y);
>}
I think he wanted t
Also it should be between two arbitrary points, so the sine wave may go from
top-right to bottom left, for example.
> On Jul 20, 2017, at 1:28 AM, Elvis Stansvik wrote:
>
> 2017-07-20 10:23 GMT+02:00 Jean-Michaël Celerier
> mailto:jeanmichael.celer...@gmail.com>>:
>> You can just compute the si
2017-07-20 10:30 GMT+02:00 Patrick Stinson :
> Also it should be between two arbitrary points, so the sine wave may go from
> top-right to bottom left, for example.
Right, but that's just a transformation of the bezier control points
once you have them.
Elvis
>
> On Jul 20, 2017, at 1:28 AM, Elv
On Donnerstag, 20. Juli 2017 10:28:17 CEST Elvis Stansvik wrote:
> 2017-07-20 10:23 GMT+02:00 Jean-Michaël Celerier
>
> :
> > You can just compute the sine directly :
> >for(int i = 0; i < width; i++)
> >{
> >
> > int x = i;
> > int y = height / 2 + amplitude * std::sin(2 * M
