On Wed, Jan 2, 2019 at 8:39 AM <915702...@qq.com> wrote:
> i have a xml string like this:
>
>123
> 456
>
>
> how to i got List a or more generally List if the
> element has child element?
>
>
>
The general way to figure out how (and if -- Jackson does NOT guarantee it
can deserialize all
On Wed, Jan 2, 2019 at 4:09 PM matt Smith
wrote:
> I just added @JsonAnyGetter to the wrapper class and now when I write
> mapper.writeValueAsString(wrapper), it gives the expected output. I don't
> understand why but it just works!
>
> @JsonAnyGetter
> @JsonSerialize(contentUsing = Item
I just added @JsonAnyGetter to the wrapper class and now when I write
mapper.writeValueAsString(wrapper), it gives the expected output. I don't
understand why but it just works!
@JsonAnyGetter
@JsonSerialize(contentUsing = ItemRowSerializer.class)
private Map foo;
On Monday, Decem
i have a xml string like this:
123
456
how to i got List a or more generally List if the
element has child element?
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