[java programming] Re: Lab 1034 Exercise 1

2010-02-10 Thread Mark Probert
Thanks for the reply my path to jdk was fine I have now fixed it i found a sunrsasign.jar buried deep in the netbeans folder on my desktop pc, so i copied it to \fre\lib directory and now works fine On 10 Feb, 04:02, miga wrote: > On Feb 9, 11:01 pm, Mark Probert wrote:> Anyone have any > id

[java programming] Re: Lab 1034 Exercise 1

2010-02-09 Thread miga
On Feb 9, 11:01 pm, Mark Probert wrote: > Anyone have any ideas on this, I have NB 6.7.1 and this tuns fine with > the input box appearing > on my laptop i have NB 6.8 and get the debug errors below with no > input box > thanks Do you try a clean and build? Otherwise you may try to go inside Fil

[java programming] Re: Lab 1034 Exercise 1

2010-02-09 Thread Mark Probert
Anyone have any ideas on this, I have NB 6.7.1 and this tuns fine with the input box appearing on my laptop i have NB 6.8 and get the debug errors below with no input box thanks On Feb 5, 11:20 am, Mark Probert wrote: > Hi All > > I have opened the MyGradesProject OK and when I run it says Build

[java programming] Re: Lab 1034 Error: The folder "javacontrol" could not be opened because you do not have sufficient access privileges

2009-08-26 Thread Jay Samuelson
Hello, You need to set the permissions on the files. Open a console and cd to the directory containing the unzipped directory. Once you are there type this command chmod -R 755 Date: Tue, 25 Aug 2009 23:50:17 -0400 Subject: [java programming] Lab 1034 Error: The folder "javacontrol" could not

[java programming] Re: Lab 1034 Error: The folder "javacontrol" could not be opened because you do not have sufficient access privileges

2009-08-26 Thread miga
On Aug 26, 5:50 am, Gian-Gabriel Cappuccio wrote: > Hello, > I am doing the Lab 1034. > Link:http://www.javapassion.com/handsonlabs/javacontrol/index.html > > I have downloaded and unziped the file 1034_javacontrol.zip but when I try > to enter to the javacontrol folder the systems says: "The

[java programming] Re: lab-1034 controls

2009-08-22 Thread Marco Versele
Merouen, Have a look in javadoc: java.text.NumberFormat and java.text.DecimalFormat classes. You will have to import these. The code goes something like: NumberFormat nf = new DecimalFormat("###"); System.out.println("number is " + nf.format(number); Merouen Ballout wrote: as example code

[java programming] Re: Lab 1034

2009-07-22 Thread Kaka madiba
I believe the problem is with your blocks unless if it was typo, try it this way, the i++ should be within the while block:   int 0;   while (i wrote: From: David Seto Subject: [java programming] Lab 1034 To: javaprogrammingwithpassion@googlegroups.com Date: Wednesday, July 22, 2009, 11:04 AM

[java programming] Re: Lab 1034

2009-07-22 Thread pacior
You created a scope. incrementation of i variable must be executed in while loop. In order to do this, write this: int i = 0; while (i wrote: > Hello all on lab 1034 homework assignment > > When I run the program and type in the 1st name on the list "Beah" no > problem. > > Name found

[java programming] Re: Lab 1034

2009-07-22 Thread cwleveke
Is there a way to walk through step by step to see what var values are. Specifically a for loop? In command prompt and net beans, is there a lesson on this? Sent on the Sprint® Now Network from my BlackBerry® -Original Message- From: "David Seto" Date: Wed, 22 Jul 2009 11:04:30 To:

[java programming] Re: Lab 1034

2009-07-22 Thread Babu Rajendran
Hi David, The increment statement should be part of the while loop. In your program, the block in which you have incremented the value of i will be unreachable. The while loop runs infinitely for any value of name other than the 1st name. So, place the incrementation part inside the while loop an

[java programming] Re: lab-1034 controls

2009-07-20 Thread Diogo Oliveira
Ups, forgot to CC the group. Repost: Hi guys, Sorry but I don't get it. Merouen, as I understand your question, when you print (display) the double value 'average', either you only see the integer part (before the decimal seperator), or you think you won't see the rest. If the 'average' variab

[java programming] Re: lab-1034 controls

2009-07-19 Thread Juan Hdz.
divide average by 3.0 then you can use the static String.format() method: average = (mathGrade + historyGrade + scienceGrade) / 3.0; System.out.println(String.format("%.2f", average)); On Jul 18, 4:41 pm, Merouen Ballout wrote: > as example code 1.11 the average is declared like  primitive typ

[java programming] Re: lab-1034 controls

2009-07-18 Thread miga
On Jul 18, 11:41 pm, Merouen Ballout wrote: > as example code 1.11 the average is declared like  primitive type > double so in the output it should be double , so what's method can be > used in order to  to display after point? See the class DecimalFormat, read the javadoc, especially the expla

[java programming] Re: Lab-1034 assignment question

2009-07-16 Thread Diogo Oliveira
Hi Will, The loop is just to find the name you entered. Use JOptionPane to display if it did find it or not. Just like exercice to, except that it should use another way to loop through the name list array. Hugs On Wed, Jul 15, 2009 at 2:10 AM, William Espinosa wrote: > Hey all, > > I have a

[java programming] Re: LAB 1034

2009-01-30 Thread Bernard FitzGerald
Hi there, When working with while loops there are a few conditions to consider. In the for loop you can see the initial state, the boolean test and lastly what happens after each loop. In the following for loop the initial state is that there is an integer 'i' equal to the value 0. Second

[java programming] Re: LAB-1034 Exercise 3 - Correction needed

2009-01-19 Thread lesh59
Also in exercise 3.2 the same problems so should be changed to do-while structure in this case. Thanks On Jan 19, 11:38 pm, lesh59 wrote: > Also further down it says > > Study how for loop control structure is used, whose code fragment is > highlighted in bold font in Code-3.11 below. > > agai

[java programming] Re: LAB-1034 Exercise 3 - Correction needed

2009-01-19 Thread lesh59
Also further down it says Study how for loop control structure is used, whose code fragment is highlighted in bold font in Code-3.11 below. again I think this should say Study the while loop control structure . On Jan 19, 2:22 am, lesh59 wrote: > In the file 1034_javacontrol.zip > > Ste

[java programming] Re: Lab 1034 (1.06)

2008-12-11 Thread Michal Eibl
Hi. You can exit your loop only in case when you reach the maximum index, but you increment the index only when you find the right result. So you have to find the right name length-times to finish the loop. Try this: int i=0; while (i > I am having trouble converting the homework form a for loo

[java programming] Re: Lab 1034 (1.06)

2008-12-11 Thread ThanhTan
I think Constantine J Coutsoukes wrote true beacause the Jennifer Cook's while loop have while (i the while loop will run fail. --~--~-~--~~~---~--~~ To post to this group, send email to javaprogrammingwithpassion@googlegroups.com To unsubscribe from this group,

[java programming] Re: Lab 1034 (1.06)

2008-12-10 Thread DenS1950
Jennifer, You are only incrementing i with i++ if you found the name. Move i++ out of the if statement or add and else clause and put it there! DenS Jennifer Cook wrote: I am having trouble converting the homework form a for loop to a while loop.   Here is the for loop:  for

[java programming] Re: Lab 1034 (1.06)

2008-12-10 Thread Constantine J Coutsoukes
Take i++; out of your if clause. It will only increment when .equals is true . int i=0; while (imailto:[EMAIL PROTECTED] On Behalf Of Jennifer Cook Sent: Wednesday, December 10, 2008 3:02 PM To: Free Java Programming Online Training Course By Sang Shin Subject: [java programming] Lab 1034

[java programming] Re: Lab 1034 (1.06)

2008-12-10 Thread belmars
Hello. I think you have to increment your counter AFTER action like that: int i=0; while (i wrote: > I am having trouble converting the homework form a for loop to a while loop. > > Here is the for loop: >  for (int i=0; i             if (names [i ].equals(searchName)){ >