and may even be slower.
>
> $('#hide-btn'), $('#FormID'), $('#display-div')
>
> - ricardo
>
> On Oct 29, 10:19 am, Tallu <[EMAIL PROTECTED]> wrote:
>
>
>
> > I am trying to show and hide a div once some data is processed b
I am trying to show and hide a div once some data is processed by the
php.but the second event is not working.What am i doing wrong?
$(document).ready(function(){
//alert("Document is Ready");
$("form#FormID").submit(function(){
//alert("Form is submitted");
Java script code.
$(document).ready(function(){
alert("Document is Ready");
$("form#FormID").submit(function(){
alert("Form is submitted");
$.post("process.php",{keyword:$("#keyword").val()},function(data)
{
alert("Data L
I am trying to use the ajax functions of JQuery but its not working
all the normal functions of jQuery are working as expected.What could
i be doing wrong.
Thanks!!
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