Thanks! That did the trick. Very much appreciated.
Roi
On Tue, Sep 29, 2009 at 12:09 PM, Charlie Griefer <charlie.grie...@gmail.com
> wrote:
> $('p[id=' + myClr + ']').addClass('bold');
>
> you need to concatenate the variable in with the literal text so it can be
> evaluated.
>
>
> On Tue, Sep 29, 2009 at 10:59 AM, roi <roi.agn...@gmail.com> wrote:
>
>>
>> I am trying to do something that seems very simple, but can not get to
>> work! Basically, I want to find an element whose ID equals a certain
>> value, as represented by a variable. The variable is derived from a
>> dropdown list. Here is my code:
>>
>> $(document).ready(function(){
>> $("select").change(function() {
>> var myClr = $("select").val();
>>
>> $("p[id=myClr]").addClass("bold"); //this is the line giving me
>> trouble
>> });
>> });
>>
>> I am wondering if it is legal to use a variable within the filter - if
>> I replace it with an actual ID value it works fine, but when I
>> substitute the variable name nothing happens.
>>
>> I am sure I am doing something dumb! Thanks for any suggestions.
>>
>> Roi
>>
>
>
>
> --
> Charlie Griefer
> http://charlie.griefer.com/
>
> I have failed as much as I have succeeded. But I love my life. I love my
> wife. And I wish you my kind of success.
>
