I have a search process with jQuery+Php... I have to use " .... like '%entered_keyword%' ..." in mysql query.
Here is the problem the Php changes "%" to " " However, when someone enters "% % % % % % % %" (8 times percent sign), it brings all datas on mysql. If i use the changing function two times like changepercentsign(percentsign($entered_keyword)) 8 times doesnt work but for this time "% % % % % % % % % % % % % % %" (15 times percent sign) works and brings all datas. What do you think? How can i get rid of this?
