That sort of helped, unfortunately I'll have multiple inputs that have
the same name. And with that code I wouldn't be able to say i have
this DOM object, get me the firstname. But, it was good to get to
know some more of the syntax.
Ends up the better solution, at least for my case, is just
Just use an attribute selector. For example:
$('input[name=firstName]')
http://docs.jquery.com/Selectors/attributeEquals#attributevalue
--Karl
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Mar 26, 2009, at 10:04 AM, Flavouski wrote:
In JQuery I saw you can
Which treeView plugin are you using?
http://jquery.bassistance.de/treeview/demo
http://be.twixt.us/jquery/treeView.php
The second one collapses and expands when you click on [-]/[+] links
only... probably what you want...
Read jQuery HowTo Resource - http://jquery-howto.blogspot.com
Hi;
you has a lot of sintaxis errors;
I have written your code again and now works fine:
!DOCTYPE html PUBLIC -//W3C//DTD XHTML 1.0 Transitional//EN
http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd;
html xmlns=http://www.w3.org/1999/xhtml;
head
meta http-equiv=Content-Type
Hi;
you has a lot of sintaxis errors;
I have written your code again and now works fine:
!DOCTYPE html PUBLIC -//W3C//DTD XHTML 1.0 Transitional//EN http://
www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd
html xmlns=http://www.w3.org/1999/xhtml;
head
meta http-equiv=Content-Type
Place this inside the plugin closure:
jQuery.fn.rte.disableDesignMode = function(iframe, submit) {
disableDesignMode(iframe, submit);
}
Then call it using
jQuery.fn.rte.disableDesignMode(x,y);
Better still, ask the author to add this as a public function.
On Jan 29, 3:48 pm, kgosser
On Mon, Dec 22, 2008 at 7:20 AM, heohni
heidi.anselstet...@consultingteam.de wrote:
This: status.addClass(the_new_status);
prints the new status, but the browser does not show the image which
is connected with the new status class?
Can I somehow refresh the div only? Is that possible?
Hi Brian!
your idea was great! Thanks! It works all very well expect one little
piece
On 11 Dez., 18:50, brian bally.z...@gmail.com wrote:
Something like this:
$(document).ready(function(){
$('div.statusimg').click(function() {
var status = this;
Hi, is there someone who can give me a hand with that topic? Please?
On 11 Dez., 16:30, heohni [EMAIL PROTECTED]
wrote:
Hi,
this is my first post, I hope I do everything right!
I have a list of users and for each user I have a little img showing
the actual status which is eather
- active
On Thu, Dec 11, 2008 at 10:30 AM, heohni
[EMAIL PROTECTED] wrote:
Hi,
this is my first post, I hope I do everything right!
Most of us only post questions here when we're doing something wrong ;-)
For the moment I toogle only active into inactive.
Because I do not know how to send 2
Something like this?...
$(document).ready(function() {
var sp = $('.searchpanel').hide() //hide boxes initially
, so = $('#searchoptions')
, anim = false //prevents fast clicking of second option
;
// shows all
$('a.showall', sp).click(function() {
anim = true;
//hide
Thank you! That's *exactly* the sort of thing I had in mind, and
*exactly* how I thought it might work (I just didn't know exactly how
to do it myself). Great commenting too; it'll really help me learn!
On May 8, 5:24 am, Wizzud [EMAIL PROTECTED] wrote:
Something like this?...
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