Nope, I was utilizing the scrollTop() method from dimensions.
Okay, the next time I think you made a mistake I'll rethink it a
bit. :)
On 10/19/07, Dave Methvin [EMAIL PROTECTED] wrote:
$('#divname').scrollTop( $('#divname')[0].scrollHeight );
I think you meant:
$('#divname')[0].scrollTop( $('#divname')[0].scrollHeight );
Nope, I was utilizing the scrollTop() method from dimensions.
Here's another way that avoids
$('#divname').scrollTop( $('#divname')[0].scrollHeight );
I think you meant:
$('#divname')[0].scrollTop( $('#divname')[0].scrollHeight );
Here's another way that avoids redundant selector expressions:
$('#divname').each(function(){this.scrollTop = this.scrollHeight});
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