Implementing remote methods isn't as simple as that. Your method returns undefined on the first call, and further calls will return the result of the previous validation.
Use the remote method instead: http://docs.jquery.com/Plugins/Validation/Methods/remote Jörn On Wed, May 20, 2009 at 11:08 AM, viralme <viral00...@gmail.com> wrote: > > $(document).ready(function() { > var valprod = $("#frmProduct").validate({ > onkeyup:false, > rules: { > txtProduct:{ > required: true, > minlength: 4, > productCheck: true > } > } > }); > > valprod.resetForm(); > }); > > jQuery.validator.addMethod('productCheck', function(productname) { > > var postURL = "product/confirm_prod"; > > $.ajax({ > cache:false, > async:false, > type: "POST", > data: "txtProduct=" + productname, > url: postURL, > success: function(msg) { > result = (msg=='TRUE') ? true : false; > }, > }); > return result; > }, 'Record Found' > ); > > my only issue is whenever 1st time it checks the record if found > record it display message Record Found but whenever i try to change my > textbox value it still gives me this message. it does not get reset if > record not found. > > >
