You should remove the @ from your selectors, they're invalid.
--John
On Thu, Apr 2, 2009 at 12:10 PM, ale wrote:
>
> Hi,
>
> I relative new to JQuery but I have some code that works fine in
> Firefox, IE and Opera, but seem to be having a problem with Chrome and
> Safari.
>
> Here is part of
Hi,
I relative new to JQuery but I have some code that works fine in
Firefox, IE and Opera, but seem to be having a problem with Chrome and
Safari.
Here is part of the code:
$("form#quiz_form_1").submit(function(){
alert("This is testing");
$.post("question_result.asp",{ quiz
Sure!
Created http://dev.jquery.com/ticket/4058
Hope there is some easy patch, if not, I will regret to 1.2.6 inmediately :(
2009/2/3 John Resig
>
> That's odd. Could you file a bug on this?
> http://dev.jquery.com/newticket
>
> Thanks!
>
> --John
>
>
>
> On Tue, Feb 3, 2009 at 10:39 AM, Jav
That's odd. Could you file a bug on this?
http://dev.jquery.com/newticket
Thanks!
--John
On Tue, Feb 3, 2009 at 10:39 AM, Javier Martinez wrote:
> I'm creating a component for an application I'm developing and I have
> upgraded jquery to the last version to get it's speed boost.
> After some
Thanks for the fast response.
Unfortunately it doesn't work :(
2009/2/3 Eric Garside
>
> Try this:
>
> var containerSelecteds = function() {
> return $('ul.selected', container);
> };
>
> I've had pretty good luck using that syntax instead of using .find()
> or .children(). It might solve
Try this:
var containerSelecteds = function() {
return $('ul.selected', container);
};
I've had pretty good luck using that syntax instead of using .find()
or .children(). It might solve the problem on safari (as I think the
reason I stopped using find() or children() was that the above wa
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