Don't understand when this could occur to make any sense for images
being inserted like this without an example, but at any rate...
You'll have to think about when and how this is triggered in order for
these if statements to be executed because as said, i don't understand
switch
On Jul 11, 9:51 am, noon [EMAIL PROTECTED] wrote:
Don't understand when this could occur to make any sense for images
being inserted like this without an example, but at any rate..
noon, thanks for your help, I'll give it a try.
I should have been a little more specific sorry. It's for
Perhaps sommin like this: (untested)
var clients =
[
'nike' : 'swoosh.jpg',
'addidas' : '3stripes.jpg',
'reebok' : 'rbk.jpg',
'default' : 'default.jpg'
];
var class = $(#main).attr(class);
typeof clients[class] != undefined ? insertImg(clients[class]) :
insertImage(clients['default']);
Thanks Richard, I couldn't get yours to work (my js knowledge is
pathetically rusty) and ran out of time to tinker with it, I ended up
just prepending the image to the div by class after it's randomly
added:
$(document).ready(function(){
$(#main.nike).prepend('img src=swoosh.jpg alt=nike /');
Richard's didn't work because he formed an array instead of an object
like he was planning. Replacing the [ ... ] with { ... } should've
made it work.
On Jul 11, 4:13 pm, brendan [EMAIL PROTECTED] wrote:
Thanks Richard, I couldn't get yours to work (my js knowledge is
pathetically rusty) and
Indeed it doesn't work, i would have liked JS to accept that syntax,
but alas...
Ryura, you are correct, if I had been creating an object instead of an
array it would have worked. I randomly posted my code with the
understanding that everything in JS is treated as an object (including
arrays)
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