[jQuery] Re: ajaxForm error call back

[Mike Alsup]

> How do I access my form object inside of the error callback?
>
> $('#foo').ajaxForm({
>   error: function(){
>     // where's my $('#foo') object here?
>   }
> });


One way is like this:

$('form').ajaxForm({
   beforeSerialize: function($form, opts) {
       opts.$form = $form;
   },
   error: function() {
       // access form via this.$form
       this.$form.hide();
   }
});