You could always set the ID of the cloned row:
$rowToInsert = $parentRow.clone(true);
newId = $parentRow.attr('id') + '_cloned';
$rowtoInsert.attr('id', newId);
On Oct 16, 5:51 pm, Felix <[EMAIL PROTECTED]> wrote:
> I have a form that allows user to add and delete rows as they desire,
> I tried to use the clone function but the problem is the clone give
> the same id as the previous row and causes trouble duirng form
> submission.
> Also, one of the column have input that is a JQuery datepicker, I am
> wondering if the action is going to be preserved?
>
> Thanks,
>
> Felix
