I think I led you astray... I had been reading about slice() in the 1.2 docs,
and assumed it was the same
Karl Swedberg-2 wrote:
>
> oh, of course! sorry about that. The slice() method here isn't
> actually a jQuery method. It's acting on an array instead. So, scrap
> the .filter('last'
oh, of course! sorry about that. The slice() method here isn't
actually a jQuery method. It's acting on an array instead. So, scrap
the .filter('last') and return to using .slice(-1). Doesn't matter
what version of jQuery you're using, because it's actually a native
JavaScript method in thi
errrm... thanks Karl...
but I get:
":last" is not a function
obviously, I'm not piecing this together quite right:
var arr = new Array(2)
arr[0] = $('ul#list1').size()
arr[1] = $('ul#list2').size()
arr[2] = $('ul#list3').
Hi Rolfsf,
Instead of .slice(-1), you can use .filter(':last')
--Karl
_
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Oct 24, 2007, at 3:53 PM, rolfsf wrote:
Thanks Josh & Andy!
I may not be able to upgrade to jQuery 1.2 right away - what's my
alternative
Thanks Josh & Andy!
I may not be able to upgrade to jQuery 1.2 right away - what's my
alternative for slice()?
r.
Andy Matthews-4 wrote:
>
>
> This will give you the highest val without having to loop over the array:
>
> var arr = new Array(6)
> arr[0] = "10"
> arr[1] = "5"
> arr[2] = "40"
unction(a,b){return a - b}).slice(-1)
-Original Message-
From: jquery-en@googlegroups.com [mailto:[EMAIL PROTECTED] On
Behalf Of Josh Nathanson
Sent: Wednesday, October 24, 2007 1:36 PM
To: jquery-en@googlegroups.com
Subject: [jQuery] Re: help - compare 3 lists, get the largest number of
i
You will want $("#myList").size().
Create an array with the three sizes - like var mylistsizes = [ 3, 9, 7 ].
Then, loop over the array and set a variable to the current value. On each
iteration, if the current iteration is greater than the held variable, reset
the variable to the current it
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