Try 1.2.6 or 1.3!
There was some problem with 1.2.4 and 1.2.5, it was very quickly
updated to 1.2.6.
On Jan 16, 3:54 pm, CreativeMind wrote:
> jQuery1.2.4 and browsers are IE and ff..the html source view of both
> browsers shows single class implemented that is 'xsnazzy' but the
> generated sour
jQuery1.2.4 and browsers are IE and ff..the html source view of both
browsers shows single class implemented that is 'xsnazzy' but the
generated source of both browsers shows three classes implemented
("xsnazzy top-left tabs-selected")..
On Jan 16, 7:41 pm, Balazs Endresz wrote:
> This should d
This should definitely work, with a live test page it would be much
easier to say anything about it.
What version of jQuery are you using and on which browser does it
occur?
On Jan 16, 2:48 pm, CreativeMind wrote:
> $('li.tabs-selected') also shows undefined.. i m unable to find li
> with the
$('li.tabs-selected') also shows undefined.. i m unable to find li
with the help of class 'tabs-selected'..
On Jan 16, 1:28 am, Balazs Endresz wrote:
> Now that's another one:
>
> $('li').hasClass('.tabs-selected')
> and
> $('li').is('.tabs-selected')
>
> only tell you if "li" has that class
Now that's another one:
$('li').hasClass('.tabs-selected')
and
$('li').is('.tabs-selected')
only tell you if "li" has that class or not,
if you want to select by class do this:
$('li.tabs-selected')
On Jan 15, 9:11 pm, CreativeMind wrote:
> hi,
> here is the html source of a list.
>
> cla
hi,
here is the html source of a list.
Map
--
here is the generated html source of a list.
Map
---
the problem is when i try to find $('li').hasClass('.tabs-selected'),
or $('li').is('.tabs-selected')
it returns me undefined... but it exists in the generat
I don't see any elements with that classname inside a span.
On Jan 15, 7:24 pm, CreativeMind wrote:
> hi,
> here is the html source of a list.
>
> class='xtop'>
>
>
> Map
> --
> here is the html source of a list.
>
>
>
>
> Map
> ---
> the problem is when i
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