Hi ,var name = 'Peter Wraae Marino';
var data ="name="+name;
$.ajax({
url: "http://localhost/test/gui/ajax_member.php";,
type: "GET",
data: data,
cache: false,
dataType: "json",
success: function(msg){
alert( msg);
},
error: function( XMLHttpRequest, textStatus, errorThrown ){
var t = "XMLHttpRequest: "+XMLHttpRequest+"\n";
t+= "textStatus: "+textStatus+"\n";
t+= "errorThrown: "+errorThrown+"\n";
alert( t );
}
});
in php file
just echo ur post variable like this
echo $_POST['name'];
Now u can get ur post name into alert pop up
Hope this code u wanted?
On Mon, Jun 1, 2009 at 11:39 AM, Peter Marino <marino.pe...@gmail.com>wrote:
> Hi jQuery,
> I'm very new to the json stuff (so warned)...
>
> when I try the following:
>
> var data =
> {
> "member" :
> {
> "name" : "Peter Wraae Marino"
> }
> }
>
> $.ajax({
> url: "http://localhost/test/gui/ajax_member.php";,
> type: "GET",
> data: data,
> cache: false,
> dataType: "json",
> success: function(msg){
> alert( msg );
> },
> error: function( XMLHttpRequest, textStatus, errorThrown ){
> var t = "XMLHttpRequest: "+XMLHttpRequest+"\n";
> t+= "textStatus: "+textStatus+"\n";
> t+= "errorThrown: "+errorThrown+"\n";
> alert( t );
> }
> });
>
> I get an error message saying parsing error, I assume this means my data
> format is wrong.
> but when I see how other people have used json data format then I think the
> way I did it is right?
>
> can someone help me out here?
>
> regards,
> Peter
>
> --
> Power Tumbling - http://www.powertumbling.dk
> OSG-Help - http://osghelp.com
>
--
---| Regard |---
Mohd.Tareque
