[jQuery] Re: simple(fy) data count

2009-06-06 Thread Gustavo Salomé
Sorry, i think i was sleeping when i wrote the code hehe Its $count.data('clone_count'). My mistake. 2009/6/6 Peter Marino > hi, > ok... now I tried it.. but it > seems that > > $count.('data') > > is not valid way of testing if data is there.. my javascript dies at that > point. > > peter > > On

[jQuery] Re: simple(fy) data count

2009-06-06 Thread Peter Marino
hi, ok... now I tried it.. but it seems that $count.('data') is not valid way of testing if data is there.. my javascript dies at that point. peter On Fri, Jun 5, 2009 at 11:30 PM, Gustavo Salomé wrote: > $count=$(".div_count"); > var clone_count =!$count.('data') ?1:$cont.data('clone_count')+

[jQuery] Re: simple(fy) data count

2009-06-05 Thread Peter Marino
super.. that's a step in the right direction thank you On Fri, Jun 5, 2009 at 11:30 PM, Gustavo Salomé wrote: > $count=$(".div_count"); > var clone_count =!$count.('data') ?1:$cont.data('clone_count')+1; > $count.data('clone_count',clone_count); > > 2009/6/5 Peter Marino > > Hi jQuery, >> I have

[jQuery] Re: simple(fy) data count

2009-06-05 Thread Gustavo Salomé
$count=$(".div_count"); var clone_count =!$count.('data') ?1:$cont.data('clone_count')+1; $count.data('clone_count',clone_count); 2009/6/5 Peter Marino > Hi jQuery, > I have the following: > > if ( $(".div_count").data("clone_count")==undefined ) > { > $(".div_count").data( "clone_count", 1 ); >