Thanks , great solution.
i figured out on on my own that is quite different. i don't know which
is the best i terms of performance.
i create an array "numbArray" first of the elements then i do this.
var index= $.inArray(0, numbArray);
if(index== -1)
{
//Value not found in the array.
}
This shoud do the job...
$("tr." + i).each(function() {
var ithis = $(this).find("td:lt(3)").map(function() {
if ($(this).html() === "0") {
return null;
} else {
return this;
}
}).min();
Hi min() is part of jquery calculation plugin.
if i use
var xmin = Math.min(x1, x2, x3)
example var xmin = Math.min(5, 0, 3)
the result will be 0 and i don't want that result. i would like to
have 3 as the best result.
example: compare prices that are in a database, but you haven't a
price for th
I'm not sure what youre trying to do here...
but the jQuery object does not contain the min() method as a property.
To use the Math.min method, you give the values as arguments...
var xmin = Math.min(x1, x2, x3);
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