If you're testing whether an element's display is either 'none' or
'block|inline|static|etc.' (i.e. not 'none') you can also do this:
$('#subnav-1').is(':visible')
or alternately
$('#subnav-1').is(':hidden')
Either of these returns a boolean.
On Jun 17, 11:20 pm, Jake Barnes wrote:
> So can
So can I do this?
if ($('#subnav-1').css('display') == "block") $('#subnav-1').css
('background-color', '#f00');
That is, if this element has display:block then turn the background
red?
Just a hypothetical example, of course.
On Jun 17, 10:55 pm, Ricardo wrote:
> $('#subnav-1').toggle();
>
$('#subnav-1').toggle();
http://docs.jquery.com/Effects/toggle
You can also access the display property with $('#subnav-1').css
('display');
On Jun 17, 10:02 pm, Jake Barnes wrote:
> This code works, but it seems inelegant:
>
> if ($("#subnav-1")[0].style.display == "block") $("#subnav-1")
> [
On Wed, Jun 17, 2009 at 6:02 PM, Jake Barnes wrote:
>
>
> This code works, but it seems inelegant:
>
> if ($("#subnav-1")[0].style.display == "block") $("#subnav-1")
> [0].style.display = "none";
>
> This seems to violate The One True jQuery Way:
>
> [0]
>
> I assume I'm not suppose to do that.
>
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