hi, i tryed do it
http://www.malsup.com/jquery/form/#getting-started
but my form do submit normal, and not in ajax...
so no return callback function
somebody can help-me ?
thanks
code
------------
<script type="text/javascript" src="lib/jquery.js"></script>
<script type="text/javascript" src="lib/jquery.form.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('#myForm').ajaxForm(function() {
alert("Thank you for your comment!");
var queryString = $('#myForm').formSerialize();
// the data could now be submitted using $.get,
$.post, $.ajax, etc
$.post('teste.php', queryString);
});
});
</script>
</head>
<body>
<form id="myForm" action="test.php" method="post">
Name: <input type="text" name="name" /> <br />
Comment: <textarea name="comment"></textarea>
<input type="submit" value="Submit " />
</form>
</body>
