[julia-users] How Julia do math operations

julia f(x::Float64, y::Float64) = 2x + y; julia f(10.97,23.9985) 45.9385005 The above method execution of function f returns an answer that I cannot understand. Can someone clarify? Thank you.

Re: [julia-users] How Julia do math operations

to abstract mathematics than they actually do. Those systems have been lying to you. Put another way: you just took the red pill by using Julia. -- John On Nov 4, 2014, at 11:06 AM, Neil Devadasan ndev...@gmail.com javascript: wrote: julia f(x::Float64, y::Float64) = 2x + y; julia