Re: [julia-users] Defining part of a function outside its module

2016-04-02 Thread jock . lawrie
Great, thanks Mauro, most helpful. On Friday, April 1, 2016 at 4:09:30 PM UTC+11, Mauro wrote: > > Maybe like so: > > julia> module Myfunc > export f > f(x) = g(x) * g(x) > function g end >end > > julia> using Myfunc > > julia> f(4) > ERROR: MethodErr

Re: [julia-users] Defining part of a function outside its module

2016-03-31 Thread Mauro
Maybe like so: julia> module Myfunc export f f(x) = g(x) * g(x) function g end end julia> using Myfunc julia> f(4) ERROR: MethodError: `g` has no method matching g(::Int64) in f at none:3 julia> Myfunc.g(x) = 2x g (generic function with 1 method) julia> f(

[julia-users] Defining part of a function outside its module

2016-03-31 Thread jock . lawrie
Hi all, This works: f(x) = g(x) * g(x) g(x) = x + 1 f(2)# 9 That is, f(x) isn't fully defined until g is defined. But if f(x) is in a module it doesn't work: module myfunc export f f(x) = g(x) * g(x) end using myfunc g(x) = x + 1 f(2) # ERROR: UndefVarError: g not defined That is,