julia> 1 | 2
3
julia> 1 & 2
0
julia> 1 + 2
3
julia> 1 $ 2
3
julia> |(1, 2)
3
julia> &(1, 2)
ERROR: unsupported or misplaced expression &
julia> +(1, 2)
3
julia> $(1, 2)
ERROR: unsupported or misplaced expression $
Is & used in some way julia that makes &(1, 2) potentially ambiguous?
Apologies if
I believe it is because of the use of & in ccall as a pseudo-operator to
pass the address of a scalar. Jeff will have to confirm or deny this though.
On Mon, Sep 8, 2014 at 10:25 PM, Dan Luu wrote:
> julia> 1 | 2
> 3
> julia> 1 & 2
> 0
> julia> 1 + 2
> 3
> julia> 1 $ 2
> 3
> julia> |(1, 2)
> 3
Anyt unary operator defined as a `syntatic_unary_operator`
https://github.com/jakebolewski/JuliaParser.jl/blob/master/src/lexer.jl#L103
is special cased by the parser and works similarly.
On Monday, September 8, 2014 4:31:48 PM UTC-4, Stefan Karpinski wrote:
>
> I believe it is because of the u
Not true, & is an undocumented singular case (regrettably). - is a unary
operator, too, but nonetheless, -(1,5) gives -4, as it well should.
Am Dienstag, 9. September 2014 00:41:01 UTC+2 schrieb Jake Bolewski:
>
> Anyt unary operator defined as a `syntatic_unary_operator`
> https://github.com/ja
On Tuesday, September 9, 2014 2:02:03 AM UTC-5, gentlebeldin wrote:
>
> Not true, & is an undocumented singular case (regrettably). - is a unary
> operator, too, but nonetheless, -(1,5) gives -4, as it well should.
>
Did you look at the link Jake posted? The `-` operator is not in the class
`syn
I would add that (&)(1,2) works; I'm imagining that it changes the context
and forces the parser to use the one legal interpretation.
