Re: [julia-users] Passing keyword arguments through a function

This worked! Didn't realize you could use ";" when calling functions. On Tuesday, July 21, 2015 at 4:49:36 PM UTC+2, Stefan Karpinski wrote: > > f(floor(x); args...) should work. > > On Tue, Jul 21, 2015 at 10:14 AM, Linus Härenstam-Nielsen < > linu...@gmail.com > wrote: > >> I am looking for a

Re: [julia-users] Passing keyword arguments through a function

On Tue, Jul 21, 2015 at 10:48 AM, Stefan Karpinski wrote: > f(floor(x); args...) should work. Relevant documentation is here[1] in case you have other confusions about keyword arguments. [1] http://julia.readthedocs.org/en/latest/manual/functions/#keyword-arguments > > On Tue, Jul 21, 2015 at 1

Re: [julia-users] Passing keyword arguments through a function

f(floor(x); args...) should work. On Tue, Jul 21, 2015 at 10:14 AM, Linus Härenstam-Nielsen < linush...@gmail.com> wrote: > I am looking for a way to automatically pass on all keyword arguments > through a function. Naively I would like to be able to do something like > this: > > f(x::Int; y::Int

[julia-users] Passing keyword arguments through a function

I am looking for a way to automatically pass on all keyword arguments through a function. Naively I would like to be able to do something like this: f(x::Int; y::Int=5, z::Int=3) = x+y+z f(x::Float64; args...) = f(floor(x), args...) But that doesn't work currently (actually, it causes StackOve