Re: [julia-users] iterate over rows of sparse matrix and get index of nonzeros?

2014-07-22 Thread Viral Shah
Julia 0.4 will have both compressed sparse column as well as compressed sparse row sparse matrices. We should probably write some iterators to work with cases such as these too. They will be convenient to use for sure, but may not give the best performance. -viral On Monday, July 21, 2014

Re: [julia-users] iterate over rows of sparse matrix and get index of nonzeros?

2014-07-22 Thread Florian Oswald
beautiful! can't wait. cheers florian On 22 July 2014 10:25, Viral Shah vi...@mayin.org wrote: Julia 0.4 will have both compressed sparse column as well as compressed sparse row sparse matrices. We should probably write some iterators to work with cases such as these too. They will be

Re: [julia-users] iterate over rows of sparse matrix and get index of nonzeros?

2014-07-21 Thread Florian Oswald
Transposing is fine! Thanks for that! On Sunday, 20 July 2014, Odd Andersen odd.ander...@gmail.com wrote: Sparse matrices in Julia are to my understanding stored as compressed sparse columns. So it is very easy to get the nonzero elements for a given column, but not so easy for rows. To

[julia-users] iterate over rows of sparse matrix and get index of nonzeros?

2014-07-19 Thread Florian Oswald
i am looking for a way to do something like *s=sprand(3,5,0.6)* *for i in 1:size(s,1)* * mySparseRowFunction(s[i, ])* *end* I guess I'm looking for an iterator over the nonzero elements, ideally by row. Does something like this exist? I know julia uses a different format, but I'm