Ok, but first I'd better, uh, fix it.
I tried it out last night for a wider range of inputs than I
originally needed to accomodate, and found a few that didn't work out
correctly. I had made the subvi more universal than it strictly
needed to be, but had primarily tested it for a fairly restric
Cool, I've been waiting for someone to ask this question b/c I
put together a fairly nifty solution to it when I faced the same
problem. Assuming, that is, that you're making an output buffer
representing a waveform with one particular frequency and then doing a
continuous output that cycles throu
You said:
...I think it might be the huge array that I keep looping around
through shift registers and concatinate array...
The combination of "huge array" and "concatenation" is a recipe for
memory waste via fragmentation. I would have to second http://exchange.ni.com/servlet/ProcessRequest?RHIV
I've only got time now to outline some basic info; hopefully someone
will fill in the gaps. I'll mention a few terms and concepts that you
can find more info about either under the LabVIEW examples or here on
the website.
1. RTSI: This timing bus ("this set of wires") is built into
your PXI chas
Two possible answers for you, based on traditional NI-DAQ. Either
should work, though I'd recommend #2 unless there's a specific reason
you need to do #1.
1. Add a call to 'Counter Set Attribute.vi' to the configuration
chain. The attribute and the attribute value type should be 'up down'
and 'h
The trouble with shooting from the hip is when you shoot your own
foot! As I think about it now, I realize that my earlier suggestion
isn't the right way to go about it. My previous post described a type
of blending operation that would really only be appropriate for a
waveform that ought to be s
Oops, didn't proofread that my "less than" and "greater" than symbols
got interpreted as html. Here goes again on the last part:
or generally, for -10 <= j <= +10
smoothed(j) = (0.50+0.05*j)*raw(j) + (0.50-0.05*j)*raw(n-j)
smoothed(n-j) = (0.50+0.05*j)*raw(n-j) + (0.50-0.05*j)*raw(j)
Just butting in here with a fairly simple idea that doesn't get into
any filtering theory. Basically, you would just do a weighted average
of the data points near the cycle boundary, and let the weighting
factor ramp from 0 to 100% over the set of smoothed points.
For example: suppose n is the n
Je ne parle plus le francais. Il y a 20 ans depuis je l'etudie. Je
pense que je peux vous aider, mais seulement en englais.
S'il vous plait, trouvez quelqu'un qui peut lire l'englais et
expliquer mon reponse ici:
http://exchange.ni.com/servlet/ProcessRequest?RHIVEID=101&RPAGEID=135&HOID=5065000
I wrote you a long reply in the "Measurement Hardware -->
Counter/Timer" forum recently, but it was all in English. (I studied
French in school, but remember only enough to *mostly* understand your
note.)
Please reply in the "Counter/Timer" forum if you need translation
help. Perhaps someone o
10 matches
Mail list logo