Re: [Libmesh-users] Initial conditions on mesh sub-domains

2015-11-02 Thread Roy Stogner
On Mon, 2 Nov 2015, avidday wrote: > Is there an easy way to apply initial conditions selectively on different > sub-domains within a mesh? > > I have typically used ProjectSolution() to apply initial conditions using a > function, but I am working on a simulation at the moment where the gmsh > g

Re: [Libmesh-users] Neumann boundary problem for Laplace equation

2015-11-02 Thread John Peterson
On Mon, Nov 2, 2015 at 12:45 PM, tschroeder wrote: > Hi there, > > > I am trying to solve the Laplace equation for the magnetic potential in a > 3D domain (a cube). > > It's free space and does not contain any sources. > > I do have magnetometer readings for discrete points on the volume's > surf

[Libmesh-users] Initial conditions on mesh sub-domains

2015-11-02 Thread avidday
Hello! Is there an easy way to apply initial conditions selectively on different sub-domains within a mesh? I have typically used ProjectSolution() to apply initial conditions using a function, but I am working on a simulation at the moment where the gmsh generated mesh comes with pre-defined sub

[Libmesh-users] Neumann boundary problem for Laplace equation

2015-11-02 Thread tschroeder
Hi there, I am new to Libmesh, which seems to be a great and versatile tool - congrats for putting this together! After studying the examples for a while, I realized that I could need some help to get started with a specific problem. I am trying to solve the Laplace equation for the magneti

Re: [Libmesh-users] find node neighbor list

2015-11-02 Thread Xujun Zhao
Thank you, Cody. This makes sense. -Xujun On Mon, Nov 2, 2015 at 9:15 AM, Cody Permann wrote: > Xujun, > > The full data structure is populated all at once so finding them one by > one really isn't an issue. If you are working with an unstructured mesh > there's not really a better way. > > Cod

Re: [Libmesh-users] find node neighbor list

2015-11-02 Thread Cody Permann
Xujun, The full data structure is populated all at once so finding them one by one really isn't an issue. If you are working with an unstructured mesh there's not really a better way. Cody On Fri, Oct 30, 2015 at 10:39 AM Xujun Zhao wrote: > Maybe it is more clear to illustrate it in another w