Hello!
I've just curious if is it possible _not_ to link a program/lib against
its indirect dependencies. I mean if libC is linked against libB and
libB is against libA then libtool will link libC against libA, which is
not neccessary in most situations (at least not on Linux, but I guess
not
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I am trying to build libtool 1.5.6 on Tru64 Unix. using './configure
--enable-dynamic'. The 'make' dies thusly:
--
yew:/u01/home/jgold/download/libtool-1.5.6 make
No suffix list.
Making all in .
No suffix list.
CONFIG_FILES=libtoolize
On Mon, May 24, 2004 at 08:19:00AM +0200, Szombathelyi Gy?rgy wrote:
I've just curious if is it possible _not_ to link a program/lib against
its indirect dependencies. I mean if libC is linked against libB and
libB is against libA then libtool will link libC against libA, which is
not
In regard to: building libtool on Tru64 Unix, Janet Goldstein said (at...:
I am trying to build libtool 1.5.6 on Tru64 Unix. using './configure
--enable-dynamic'. The 'make' dies thusly:
Janet-
I've never seen this particular problem on Digital UNIX or Tru64 UNIX.
The obvious differences I can see
On Mon, 24 May 2004, Albert Chin wrote:
On Mon, May 24, 2004 at 08:19:00AM +0200, Szombathelyi Gy?rgy wrote:
I've just curious if is it possible _not_ to link a program/lib against
its indirect dependencies. I mean if libC is linked against libB and
libB is against libA then libtool will link libC
On Mon, May 24, 2004 at 07:32:01PM -0500, Bob Friesenhahn wrote:
On Mon, 24 May 2004, Albert Chin wrote:
On Mon, May 24, 2004 at 08:19:00AM +0200, Szombathelyi Gy?rgy wrote:
I've just curious if is it possible _not_ to link a program/lib against
its indirect dependencies. I mean if libC is
