If I have a URL like http://localhost/Test/edit/{id} and I would like the {id} transform to a parameter instead of URL path part.
The problem is that if I have a template named edit.html under webapp/ Test, which is the template I use to edit an item. And I have a Menu instance like the following: <code> Menu (Loc("Test", List("Test") -> true, "Test")) </code> It would only match URL like http://localhost/Test/edit, not anything like http://localhost/Test/edit/1 Is it best way to do it by create a menu with RewriteRequest? Because I found it a little boilerplate if I have lot URL pattern like this. <code> val menu = Menu(new Loc[Unit] { override def name = "Test" override def text = "Test" override def link = (List ("Test"), true) override def params = Nil override def defaultValue = Full(()) def isTarget (path: ParsePath) = path match { case ParsePath (List("Test", "edit", id), _, _, _) => true case _ => false } override def rewrite = Full ( NamedPF("Test") { case RewriteRequest (path, _, _) if isTarget(path) => RewriteResponse(List("Test", "edit"), Map("id" -> "1024")) -> () }) }) </code>
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