I wrote a zip function to group the list as follows:
scala> def zipListBySize[T](size: Int)(list: List[T]) : List[List[T]]
= {
| var (first, second) = list.splitAt(size)
| if (second == Nil)
| List(first)
| else
| List(first) ++ zipListBySize(size)(second)
>From the ToDo sample code... the view code:
Exclude done
1
To Do
So, you want the body of for each element.
Here's the Snippet code:
def list(html: NodeSeq) = {
If you want 5 items a line, you can use nested binds - checkout the
chooseTemplate(...) method.
Any pagination or limiting you need to do, just do that in your
snippet however you want to page your result set :-)
On Apr 13, 7:18 am, "sailormoo...@gmail.com"
wrote:
> I See...Thanks...
> and if I
No. That will get you the same name five times per line, with one line
per name. For example,
Bob Bob Bob Bob Bob
Sam Sam Sam Sam Sam
etc.
I can't think of anything but complicated ways to do this right now
because I'm exhausted, but if someone else doesn't give you one by
tomorrow, I'll try
I See...Thanks...
and if I want 5 items a line
does it work as follows?
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Hi,
On Mon, Apr 13, 2009 at 1:03 PM, sailormoo...@gmail.com
wrote:
>
> <% for (int i = 0; i < data.size(); i++) { %>
> <%= data.name %>
> <% } %>
>
>
> I cannot find an example like this, and I don't know if it should be
> done by a single snippet with all the rows, or some list/array t
I do it like this:
Let's say it's a list of companies in which the name of the company
links to the company's website.
So you have a snippet that handles these Companies. Let's call it
CompanyOps.scala. In the snippet, you have a method which we'll call
list. In the method, you get the list o
I would do this with a snippet tag that looked like:
Then the snippet would look like
class MyTable {
def foo (xhtml : NodeSeq) : NodeSeq = {
val data = ... fill this in ...
val entries =
data.flatMap(bind("entry", chooseTemplate("tb", "entries", xhtml),
"name" -> T
