I've pulled from origin and fixed a bug (don't get too excited - it
may have been the tiniest bug ever):
http://code.google.com/p/lilypond/issues/detail?id=729
I see that the most recent rule is 2.13.0, so my rule should be 2.13.x
where x >= 0. Do I use the current development version or current +
Doc build:
-master/Documentation/devel/compiling.itexi:2: warning: unreferenced
node `Compiling from source'.
makeinfo: Removing output file `out/contrib-guide.txt' due to errors;
use --force to preserve.
Dist error:
file from VC not distributed: lilypond-2.13.0/Documentation/ja/user/i18n/ja
-
On Thu, 2009-02-26 at 11:23 +0100, Michael Käppler wrote:
> Hi all,
> I don't completely understand the way how Duration::Duration(Rational r,
> bool scale) converts a rational number into a note and dots, but
> it's clear that the Completion_heads issue with splitting up breve and
> longa notes
On 2/24/09 6:53 PM, "Andrew Hawryluk" wrote:
>
> I will take a look. Any advice on identifying an easy bug vs. a very
> hard one? Most of the ones that really bother me (e.g. #379) have
> turned out to be really nasty, and therefore not a good place to
> start.
I have no great ideas for this
Both fixed. Other comments?
>From c30a3049063acb270332d6f83a43a808a4893b16 Mon Sep 17 00:00:00 2001
From: root
Date: Thu, 26 Feb 2009 13:19:48 +0100
Subject: [PATCH] This fixes an endless loop in duration.cc:67 when Duration::Duration(Rational r, bool scale) is called
with r.num() >= 2 * r.den(
Michael Käppler writes:
> Nevertheless, please test and critizize!
> +inline int
> +shift_left (int value, int shiftamount)
> +{
> + if (shiftamount < 0) return (value >> abs(shiftamount));
> + else return (value << shiftamount);
> +}
I would not use abs(shiftamount) here, but -shiftamount si
Hi all,
I don't completely understand the way how Duration::Duration(Rational r,
bool scale) converts a rational number into a note and dots, but
it's clear that the Completion_heads issue with splitting up breve and
longa notes was caused by the way << behaves when given a negative
number as s