Thanks very much, Irv, with the additional explanation you gave, I
was able to get it to work.
I appreciate your patience.
Best,
George
A few people gave you basically the same answer, and I'll give it to
you again. If you have a need for something like this, what you
really want is a li
A few people gave you basically the same answer, and I'll give it to
you again. If you have a need for something like this, what you
really want is a list. Lists are one of the most powerful features
of Lingo. Once you get your head around them, you will wonder how
you were able to get by wi
Hello to all,
I posted a similar question to this a few days ago, but from the
answers I got, I realize that I didn't make my question clear. Sorry.
I would like to try again.
I want to know if there is a way to use a repeat loop integer to name
variables so that a large numer of variables c
Buzz,
Concatenating the "text" of members will discard all formatting AND links. I
need to preserve both. That's where the problem is.
I've now devised a routine that goes through all hyperlinks for each individual
member and recreates them at the appropriate points in the new, concatenated
me
At 4:02 PM -0400 5/28/05, you wrote:
I need to concatenate several text members into one new member.
did you try?
holder = ""
repeat with CurrMem in locMemList
holder = holder & CurrMem.text
end repeat
newMember = new(#text)
newMember.text = holder
hth
-Buzz
The script below works, but a
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please call the office.
Regards,
Thomas Dwyer
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I need to concatenate several text members into one new member.
The script below works, but all hyperlinks in the text are lost:
repeat with CurrMem in locMemList
member("NewMem").rtf = member("NewMember").rtf && member("CurrMemr").rtf
end repeat
I suppose the rtf of member doesn't know anyth
