lingo-l Occurrences in a list

2005-06-30 Thread Rods
Hi, How is the best way to count the occurrences of values in a list? I have a list with 6000+ random generated numbers and I need to count how many times each of one appear. Thank's in advance Rodrigo Peres [To remove yourself from this list, or to change to digest mode, go to

Re: lingo-l Occurrences in a list

2005-06-30 Thread Bart Pietercil
you could try to 1) sort the list from low to high 2) count the list (so you have the total number of items in the list) 3) the trick x = getPos(mysortedlist,mysortedlist[nrofitemsinthelist]) -- this will give you the FIRST occurence of the last item in the list y = mysortedlist[x-1]) --gives

Re: lingo-l Occurrences in a list

2005-06-30 Thread Jeff Gomes
Well, you could do something like this (caution: untested e-mail Lingo)... -- aList = #linearList or #propList -- returns a #propList where -- property is a value from aList -- value is the number of occurrences of that aList value on mListValuesCounts ( aList ) if not ilk ( aList, #list )

Re: lingo-l Occurrences in a list

2005-06-30 Thread Valentin Schmidt
here some code that doesn't use any (lingo) repeat loop, so might be a bit faster (but only works for lists that contain numbers only): on howMany (tList, tValue) tmp = tList.duplicate() tmp.sort() n = tmp.getPos(tValue) if n = 0 then return 0 tmp = - tmp tmp.sort() return (tmp.count +

Re: lingo-l Occurrences in a list

2005-06-30 Thread Buzz Kettles
-- here's my take (similar to others) -- it creates a proplist with -- propnames = the occurance names -- values = the counts -- (email Lingo) on cnt inList testList = inList.duplicate() testList.sort() outPList = [:] pCount = testList.count repeat with i = 1 to pCount pTarget =