This is called a Ceiling function. The opposite, where you want to lop off
the non-integer part is called a Floor function.
Looking in my Math library of code, I see that my Floor and Ceiling
functions aren't correct, so let's see
I just leveraged the working Floor function to create the
if x > integer(x) then x = x+1
Colin Holgate wrote:
>
> >put integer(1.9 + 0.5)
> >-- 2
> >
> >Regards,
> >Pranav Negandhi
>
> Unfortunately that would not work out:
>
> put integer(1.0 + 0.5)
> -- 2
>
> The goal was to let 1.0 be 1.
>
> Here's something that does work, but I feel sure there
Hows this? :-)
n = 4.1
z = (n - integer(n - 0.5))
put n - (n - integer(n-.5)) + (z > 0)
-- 5.
Works like a charm, Colin. Just for the heck of it I went through it all.
Took a while to make out though. I removed the multiplication with the
boolean result at the end. I think it's redundant.
Simpler?
put integer(n + .5) - (integer(n) = n)
_
Colin Holgate wrote:
> The goal was to let 1.0 be 1.
>
> Here's something that does work, but I feel sure there's something
> simpler (it can be simpler in two lines, but just for the fun of it
> I'm trying one line):
>
> put n - (n - integer
Sent by:cc:
[EMAIL PROTECTED] Subject: Re:
Rounding (unusually)
>put integer(1.9 + 0.5)
>-- 2
>
>Regards,
>Pranav Negandhi
Unfortunately that would not work out:
put integer(1.0 + 0.5)
-- 2
The goal was to let 1.0 be 1.
Here's something that does work, but I feel sure there's something
simpler (it can be simpler in two lines, but just for the fun of it
put integer(1.2 + 0.5)
-- 2
put integer(1.6 + 0.5)
-- 2
put integer(1.9 + 0.5)
-- 2
Regards,
Pranav Negandhi
I'd like to round a number the following way.
1.2 would round up to 2
1.9 would round up to 2
1.99 would still round to 2
[To remove yourself from this list, or to change to
A little stuck on this..
I'd like to round a number the following way.
1.2 would round up to 2
1.9 would round up to 2
1.99 would still round to 2
Basically if its over the whole of the number it needs to go to the next
whole number.
Any ideas?
Cheers
Brendon
[To remove yourself from this
