Hi list!
Can anyone help me with a problem i have?
i've written a c++ program (using kdevelop under radhat 7.1) which takes 12
parameters. i need to run it several hundred times, changing each time
another parameter. in order to do this another program was writen with a
for loop in it.
the loop
On Tue, 10 Jul 2001, b g wrote:
the loop contains system() comand, that boots the big program. everything
goes ok untill i logout. when i do logout, the programs are killed.
how can i prevent this?
two ways:
a. by making your program a daemon. daemons are unix processes which run
without a
this another program was writen with a
for loop in it.
the loop contains system() comand, that boots the big program. everything
goes ok untill i logout. when i do logout, the programs are killed.
how can i prevent this?
This is not a C++ question.
How about running the parent program using 'batch
Dear bg!
The most common solution is: do not log-out... Heh. Well, there are some
better ones.
I had a problem of the kind a short while ago and here is a way to avoid
hangup: You have to run Your program disabling any input or output. Here
is a sample command-line:
/myprog /dev/null
On 10 Jul 2001 12:18:17 +0300, mulix wrote:
On Tue, 10 Jul 2001, b g wrote:
the loop contains system() comand, that boots the big program. everything
goes ok untill i logout. when i do logout, the programs are killed.
how can i prevent this?
two ways:
A thrid way:
Run it with the
On Tue, 10 Jul 2001, b g wrote:
Hi list!
Can anyone help me with a problem i have?
Yes. But please refrain from cross-posting.
i've written a c++ program (using kdevelop under radhat 7.1) which takes 12
parameters. i need to run it several hundred times, changing each time
another
