I had previously decided that tagging a single multiorder entry would
count as tagging 2^order entries for the purposes of 'nr_to_tag'.
I now believe that decision to be a mistake, and it should count as a
single entry. That's more likely to be what callers expect.
When walking back up the tree
I had previously decided that tagging a single multiorder entry would
count as tagging 2^order entries for the purposes of 'nr_to_tag'.
I now believe that decision to be a mistake, and it should count as a
single entry. That's more likely to be what callers expect.
When walking back up the tree
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