Chao Xie writes:
> The original pxa_rtc_open/pxa_rtc_release will be called
> when the /dev/rtc0 is opened or closed.
> In fact, these two functions will register/unregister the irqs.
> User application will use /dev/rtc0 to read the rtc time or set
> the alarm. The rtc should still run indepent
On Wed, Nov 28, 2012 at 09:21:10PM -0500, Chao Xie wrote:
> The original pxa_rtc_open/pxa_rtc_release will be called
> when the /dev/rtc0 is opened or closed.
> In fact, these two functions will register/unregister the irqs.
> User application will use /dev/rtc0 to read the rtc time or set
> the
On Wed, Nov 28, 2012 at 09:21:10PM -0500, Chao Xie wrote:
The original pxa_rtc_open/pxa_rtc_release will be called
when the /dev/rtc0 is opened or closed.
In fact, these two functions will register/unregister the irqs.
User application will use /dev/rtc0 to read the rtc time or set
the alarm.
Chao Xie chao@marvell.com writes:
The original pxa_rtc_open/pxa_rtc_release will be called
when the /dev/rtc0 is opened or closed.
In fact, these two functions will register/unregister the irqs.
User application will use /dev/rtc0 to read the rtc time or set
the alarm. The rtc should
The original pxa_rtc_open/pxa_rtc_release will be called
when the /dev/rtc0 is opened or closed.
In fact, these two functions will register/unregister the irqs.
User application will use /dev/rtc0 to read the rtc time or set
the alarm. The rtc should still run indepent of open/close the
rtc
The original pxa_rtc_open/pxa_rtc_release will be called
when the /dev/rtc0 is opened or closed.
In fact, these two functions will register/unregister the irqs.
User application will use /dev/rtc0 to read the rtc time or set
the alarm. The rtc should still run indepent of open/close the
rtc
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