On 19 April 2018 at 17:59, Gustavo A. R. Silva wrote:
> Currently, the code block inside the for loop will never execute
> more than once, because the function returns inmediately after
> the first iteration, hence the execution of the code at the second
> iteration is structurally dead and, code
On 19/04/18 18:59, Gustavo A. R. Silva wrote:
> Currently, the code block inside the for loop will never execute
> more than once, because the function returns inmediately after
> the first iteration, hence the execution of the code at the second
> iteration is structurally dead and, code at line 2
2018-04-20 0:59 GMT+09:00 Gustavo A. R. Silva :
> Currently, the code block inside the for loop will never execute
> more than once, because the function returns inmediately after
> the first iteration, hence the execution of the code at the second
> iteration is structurally dead and, code at line
Currently, the code block inside the for loop will never execute
more than once, because the function returns inmediately after
the first iteration, hence the execution of the code at the second
iteration is structurally dead and, code at line 281: return 0; is
never reached.
Fix this by checking
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