On Tue 11-06-19 12:16:35, Chengang (L) wrote:
> Hi Michal
>
>
> >On Sun 09-06-19 17:10:28, ChenGang wrote:
> >> Usually the value of min_free_kbytes is multiply of 4, and in this
> >> case ,the right shift is ok.
> >> But if it's not, the right-shifting operation will lose the low 2
> >> bits,
Hi Michal
>On Sun 09-06-19 17:10:28, ChenGang wrote:
>> Usually the value of min_free_kbytes is multiply of 4, and in this
>> case ,the right shift is ok.
>> But if it's not, the right-shifting operation will lose the low 2
>> bits, and this cause kernel don't reserve enough memory.
>> So it's
Hi Wei Yang
>On Sun, Jun 09, 2019 at 05:10:28PM +0800, ChenGang wrote:
>>Usually the value of min_free_kbytes is multiply of 4, and in this case
>>,the right shift is ok.
>>But if it's not, the right-shifting operation will lose the low 2 bits,
>But PAGE_SHIFT is not always 12.
You are
On Sun 09-06-19 17:10:28, ChenGang wrote:
> Usually the value of min_free_kbytes is multiply of 4,
> and in this case ,the right shift is ok.
> But if it's not, the right-shifting operation will lose the low 2 bits,
> and this cause kernel don't reserve enough memory.
> So it's necessary to align t
On Sun, Jun 09, 2019 at 05:10:28PM +0800, ChenGang wrote:
>Usually the value of min_free_kbytes is multiply of 4,
>and in this case ,the right shift is ok.
>But if it's not, the right-shifting operation will lose the low 2 bits,
But PAGE_SHIFT is not always 12.
>and this cause kernel don't reserv
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