Hello.
Peter Zijlstra wrote:
> > So, I don't need to grab a reference to "ptr"
> > because memory region pointed by "ptr" will never be kfree()ed.
> > And it is legal to use "ptr" after rcu_read_unlock()
> > because memory region pointed by "ptr" will never be kfree()ed.
>
> Still think that is a
On Mon, 2007-10-08 at 01:56 +0900, Tetsuo Handa wrote:
> So, I don't need to grab a reference to "ptr"
> because memory region pointed by "ptr" will never be kfree()ed.
> And it is legal to use "ptr" after rcu_read_unlock()
> because memory region pointed by "ptr" will never be kfree()ed.
Still
Hello.
Jun WANG wrote:
> I'm sorry,I think I got your idea, if you do not need ptr in
> my_task_that_may_sleep(), why you need to grab a reference to "ptr". If
> your my_task_that_may_sleep() needs ptr, and according to the
> "memory region pointed by "ptr" never be removed." you say,
> it is ok
> Hello.
>
> Thank you for pointing out.
>
> Jun WANG wrote:
> > >rcu_read_lock();
> > >list_for_each_rcu(p, ...) {
> > > ptr = list_entry(p, struct ..., list);
> > > /* Grab a reference to "ptr". */
> > > rcu_read_unlock();
> > > my_task_that_may_sleep(ptr);
> > > rcu_read_lock();
> >
Hello.
Thank you for pointing out.
Jun WANG wrote:
> >rcu_read_lock();
> >list_for_each_rcu(p, ...) {
> > ptr = list_entry(p, struct ..., list);
> > /* Grab a reference to "ptr". */
> > rcu_read_unlock();
> > my_task_that_may_sleep(ptr);
> > rcu_read_lock();
> > /* Drop a reference to
Hello.
Peter Zijlstra wrote:
> > Can I sleep between rcu_read_lock() and rcu_read_unlock() ?
> > As far as I saw, rcu_read_lock() makes in_atomic() true, so I think I can't
> > sleep.
> You can indeed not sleep in an rcu_read_lock() section. However, you
> could grab a reference on an item, stop
6 matches
Mail list logo
